PHYSICS / CHAPTER 41

Electric forces, fields and charge distributions

Use vectors, integration and symmetry to choose the right method for an electrostatic field.

12 sections10 worked examples9 checks to tryRead at your own pace

A tiny charged particle can reveal the influence of charges it never touches. Electric field is our way of describing that influence at each location. Start with direction and superposition; the formula becomes useful once we know whose field and whose force we are finding.

This chapter develops three methods: direct vector addition, integration over charge elements and Gauss’s law. The central skill is deciding which method the source symmetry actually supports.

What you will learn to do

  • Use signed Coulomb forces and distinguish a field from the force on a test charge.
  • Add source components and identify admissible zero-field regions.
  • Set up line, ring and disk integrals with correct charge elements.
  • Check field expressions by near and far limits.
  • Interpret electric flux as a signed surface integral.
  • Use Gauss’s law only with justified symmetry when extracting E.
  • Distinguish insulating volume charge, shells and conducting equilibrium.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

BEFORE YOU READ

Bring back one idea

Try a sentence or a sketch before opening the comparison. If this is new, use the explanation to get started.

If the test charge changes sign, does the electric field created by the unchanged source charges reverse?

Compare your reasoning

No. The source field stays the same. The force on the test charge reverses because force is charge times field. Keep the property of the surroundings separate from the response of the probe.

Revisit the explanation →

01 / Electric forces, fields and charge distributions

Start with the interaction between two point charges

Electric charge has a sign as well as a magnitude. Two point charges with the same sign repel and opposite signs attract. In electrostatics in vacuum, Coulomb’s law gives the force magnitude k|q₁q₂|/r², where k = 1/(4πε₀) and r is their separation.

The force acts along the line joining the charges. Each charge experiences an equal-magnitude opposite force, even if their masses or charge magnitudes differ. Their accelerations need not be equal because acceleration also depends on mass.

A point-charge model is appropriate when an object’s charge distribution can be treated as small compared with relevant distances, or when a justified symmetry gives an equivalent external field. Two nearby conducting spheres can redistribute charge, so replacing them automatically by unchanged point charges at their centres may fail.

A reliable vector expression for the force on q₂ due to q₁ uses a unit vector from q₁ toward q₂: F₂₁ = kq₁q₂ r̂₁₂/r². The signed product then reverses the force for opposite charges. If you instead use a magnitude formula, determine attraction or repulsion separately.

F21=kq1q2r2r^12,k=14πε0\mathbf F_{21}=k\frac{q_1q_2}{r^2}\hat{\mathbf r}_{12},\qquad k=\frac1{4\pi\varepsilon_0}

The unit vector points from source charge q₁ toward q₂. The examples use k = 9.0 × 10⁹ N·m²/C² where a numerical value is needed.

WORKED EXAMPLE

Separate force magnitude from force direction

A charge +2.0 μC is at x = 0 and a charge −3.0 μC at x = 0.30 m in vacuum. Find the force on the negative charge using k = 9.0 × 10⁹ N·m²/C².

Choose an approach

Compute the magnitude from absolute charges, then use attraction to set the direction.

  1. Convert microcoulombs to coulombs before multiplying.

    F=9.0×109(2.0×10−6)(3.0×10−6)(0.30)2=0.60 NF=\frac{9.0\times10^9(2.0\times10^{-6})(3.0\times10^{-6})}{(0.30)^2}=0.60\ \mathrm N
  2. Opposite charges attract toward the source at the origin.

    F21=−0.60 x^ N\mathbf F_{21}=-0.60\,\hat{\mathbf x}\ \mathrm N

What this gives usThe negative charge experiences 0.60 N toward negative x. The positive charge experiences 0.60 N toward positive x.

Check the result another way

Doubling the separation would reduce each force magnitude by four. The signs determine direction, not a negative magnitude.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Separate force magnitude from force direction
Problem: A charge +2.0 μC is at x = 0 and a charge −3.0 μC at x = 0.30 m in vacuum. Find the force on the negative charge using k = 9.0 × 10⁹ N·m²/C².

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Start with the interaction between two point charges
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
\mathbf F_{21}=k\frac{q_1q_2}{r^2}\hat{\mathbf r}_{12},\qquad k=\frac1{4\pi\varepsilon_0}
Meaning: The unit vector points from source charge q₁ toward q₂. The examples use k = 9.0 × 10⁹ N·m²/C² where a numerical value is needed.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

02 / Electric forces, fields and charge distributions

The electric field separates the source from the test charge

An electric field assigns a force per unit positive test charge to each position. Conceptually, the test charge is small enough not to disturb the source distribution. Once the source field is known, the force on another point charge is qE.

The field direction is the direction a positive test charge would be pushed. A negative test charge experiences a force opposite to E. Changing the test-charge sign does not change the already specified source field, though a large real test charge might disturb the source and invalidate the ideal test limit.

For a point source Q, E = kQ r̂/r², directed outward for positive Q and inward for negative Q. Field units are N/C, equivalently V/m when electric potential is introduced. Do not multiply by the test charge when the question asks for the field itself.

An electric field is a vector at a point. Field lines visualize its direction and relative strength, but a charged particle’s trajectory need not follow a field line when it has an initial velocity or when inertia carries it across the pattern.

E(r)=lim⁡qtest→0Fqtest,F=qE\mathbf E(\mathbf r)=\lim_{q_{\mathrm{test}}\to0}\frac{\mathbf F}{q_{\mathrm{test}}},\qquad\mathbf F=q\mathbf E

The test limit means the source distribution is not appreciably altered. Force direction reverses for negative q.

WORKED EXAMPLE

Apply a vector field to a negative charge

At a point, E = (3000 x̂ + 4000 ŷ) N/C. A charge −5.0 nC is placed there. Find its force vector and magnitude.

Choose an approach

Multiply both components by the signed charge.

  1. The negative charge reverses each field component.

    F=(−15x^−20y^) μN\mathbf F=(-15\hat{\mathbf x}-20\hat{\mathbf y})\ \mathrm{\mu N}
  2. The magnitude is the length of the force vector.

    ∣F∣=152+202=25 μN|\mathbf F|=\sqrt{15^2+20^2}=25\ \mathrm{\mu N}

What this gives usThe force is (−15 x̂ − 20 ŷ) μN with magnitude 25 μN.

Check the result another way

The field magnitude is 5000 N/C, so |q|E = 5.0 × 10⁻⁹ × 5000 = 25 μN independently.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Apply a vector field to a negative charge
Problem: At a point, E = (3000 x̂ + 4000 ŷ) N/C. A charge −5.0 nC is placed there. Find its force vector and magnitude.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

STOP & THINK

At a point with a fixed electric field, replacing a positive test charge by an equal negative charge does what?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions / The electric field separates the source from the test charge
Problem: At a point with a fixed electric field, replacing a positive test charge by an equal negative charge does what?
Choices:
1. Reverses the source field
2. Reverses the force on the test charge
3. Leaves the force unchanged

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: The electric field separates the source from the test charge
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
\mathbf E(\mathbf r)=\lim_{q_{\mathrm{test}}\to0}\frac{\mathbf F}{q_{\mathrm{test}}},\qquad\mathbf F=q\mathbf E
Meaning: The test limit means the source distribution is not appreciably altered. Force direction reverses for negative q.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

03 / Electric forces, fields and charge distributions

Add vector components, not just positive field magnitudes

For fixed source charges, the total electrostatic field is the vector sum of their individual fields. Draw each contribution at the observation point before adding components. An inverse-square magnitude alone does not indicate whether contributions reinforce or oppose.

Symmetry can remove components before any arithmetic. For two equal positive charges placed symmetrically on a horizontal axis, at a point on their perpendicular bisector the horizontal contributions cancel and the vertical contributions add. At the midpoint itself all contributions cancel.

A zero field at one point is a local statement, not a statement that the surrounding region has no field. It also does not automatically establish stable equilibrium for a free charge. Test the force under small displacements in different directions before making a stability claim.

For charges of opposite sign, the midpoint fields point from the positive charge toward the negative and add rather than cancel. The source signs must therefore be used before applying a geometric symmetry argument.

WORKED EXAMPLE

Use symmetry to reduce a two-charge field

Two equal positive charges q are fixed at x = −a and x = +a. Find the field at (0,y) for y > 0.

Choose an approach

Cancel horizontal components and retain the vertical projection from each charge.

  1. Each source is at distance √(a² + y²) from the point.

    Eone=kqa2+y2E_{\mathrm{one}}=\frac{kq}{a^2+y^2}
  2. The vertical projection factor is y divided by that distance.

    Ey=2kqa2+y2ya2+y2=2kqy(a2+y2)3/2E_y=2\frac{kq}{a^2+y^2}\frac{y}{\sqrt{a^2+y^2}}=\frac{2kqy}{(a^2+y^2)^{3/2}}
  3. The horizontal components cancel by reflection symmetry.

    Ex=0E_x=0

What this gives usThe field points upward with magnitude 2kqy/(a² + y²)^(3/2).

Check the result another way

At y = 0 the result is zero. Far above the pair, y ≫ a, it approaches 2kq/y², the field of total charge 2q viewed from far away.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Use symmetry to reduce a two-charge field
Problem: Two equal positive charges q are fixed at x = −a and x = +a. Find the field at (0,y) for y > 0.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Add vector components, not just positive field magnitudes
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
Build the physical reasoning before choosing an equation.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

04 / Electric forces, fields and charge distributions

Check regions and directions before solving an equality

On the line joining two like charges, fields oppose between them, so a cancellation point may lie there. Outside the pair, their fields point the same way and cannot cancel. For opposite charges, the between-charge fields add, so any finite cancellation point must lie outside and generally on the side of the smaller magnitude.

After identifying an admissible region, equate magnitudes and solve with distances appropriate to that region. Squaring equations can introduce algebraic candidates inconsistent with the direction analysis. Always substitute the candidate back into the vector picture.

An electric-field zero does not depend on the value of a sufficiently small test charge. A force balance that also includes gravity, tension or another interaction is a different problem and may depend on the test object’s mass and charge.

WORKED EXAMPLE

Find a cancellation point with a region check

Two fixed positive charges +q and +4q lie at x = 0 and x = 0.60 m. Find the finite zero-field point on their connecting line.

Choose an approach

Fields can oppose only between the like charges; let its distance from +q be x.

  1. Equate the opposing magnitudes in the allowed interval.

    kqx2=4kq(0.60−x)2\frac{kq}{x^2}=\frac{4kq}{(0.60-x)^2}
  2. Both distances are positive in that interval, so take positive square roots.

    0.60−x=2x0.60-x=2x
  3. Solve and retain the point between the charges.

    x=0.20 mx=0.20\ \mathrm m

What this gives usThe zero-field point is 0.20 m from +q and 0.40 m from +4q.

Check the result another way

The stronger charge is twice as far away, so its fourfold charge is exactly offset by four times the distance squared. Outside the pair the fields reinforce, excluding other finite line solutions.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Find a cancellation point with a region check
Problem: Two fixed positive charges +q and +4q lie at x = 0 and x = 0.60 m. Find the finite zero-field point on their connecting line.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Check regions and directions before solving an equality
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
Build the physical reasoning before choosing an equation.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

05 / Electric forces, fields and charge distributions

Replace a charge sum with a geometrically defined integral

For charge distributed continuously, divide it into small elements dq and add their vector fields by integration. Use dq = λ dl for a line, dq = σ dA for a surface, or dq = ρ_q dV for a volume. The charge-density units are C/m, C/m² and C/m³ respectively.

Choose the integration element to exploit symmetry. A ring element can combine an entire azimuthal set whose sideways fields cancel. A straight-line element may be more suitable for a finite rod. The source-to-observation distance usually varies with the integration variable and must remain inside the integral.

The vector form is E(r) = k∫(r − r′) dq/|r − r′|³. The primed coordinate locates source charge; the unprimed coordinate locates the observation point. Confusing those roles can produce an incorrect projection or a denominator missing a power of distance.

After integration, test dimensions, symmetry and limiting cases. A compact distribution of total charge Q should look like kQ/r² sufficiently far away when its net charge is nonzero. A result that fails that limit deserves rechecking before numerical substitution.

E(r)=k∫r−r′∣r−r′∣3 dq\mathbf E(\mathbf r)=k\int\frac{\mathbf r-\mathbf r\prime}{|\mathbf r-\mathbf r\prime|^3}\,dq

This electrostatic vacuum expression adds source elements vectorially. A symmetry argument can simplify components before integration.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Replace a charge sum with a geometrically defined integral
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
\mathbf E(\mathbf r)=k\int\frac{\mathbf r-\mathbf r\prime}{|\mathbf r-\mathbf r\prime|^3}\,dq
Meaning: This electrostatic vacuum expression adds source elements vectorially. A symmetry argument can simplify components before integration.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

06 / Electric forces, fields and charge distributions

A uniformly charged ring gives an axial field with a useful maximum

For a uniform ring of radius R, every charge element is the same distance √(R² + z²) from an observation point on its axis. Opposite elements cancel their transverse components, leaving only the axial projection.

Each element contributes dE_z = k z dq/(R² + z²)^(3/2). The geometric factor is constant around the ring, so integrating dq simply gives the total charge Q. For positive Q and z > 0, the field points along positive z.

At the ring centre, the field vanishes by symmetry. Far from the ring, the expression approaches the point-charge field kQ/z². Near the centre, it grows approximately linearly as kQz/R³. These limits explain why its magnitude must rise from zero and later fall.

A zero axial field at the centre is not a proof of three-dimensional trapping. The response to off-axis displacements must also be considered. Electrostatic equilibrium and stability are separate questions.

Ez=kQz(R2+z2)3/2E_z=\frac{kQz}{(R^2+z^2)^{3/2}}

Uniform ring, axial observation point. The expression is signed through z and Q.

Inspect the axial field of a charged ring

000.10.750.21.50.32.250.43E_z / (kQ/R²)z/R
Positive uniform ring
0
The normalized axial field rises from zero, reaches a maximum near z/R = 0.707 and then decreases. Samples join the exact ring-field values. Lines connect the plotted samples.

WORKED EXAMPLE

Locate the strongest axial field by differentiation

For a positive uniformly charged ring, find where E_z is maximum on the positive axis.

Choose an approach

Differentiate the axial field while treating Q and R as constants.

  1. Differentiate the product z(R² + z²)^(−3/2).

    dEzdz=kQR2−2z2(R2+z2)5/2\frac{dE_z}{dz}=kQ\frac{R^2-2z^2}{(R^2+z^2)^{5/2}}
  2. Set the numerator to zero for the stationary point.

    z=R2z=\frac{R}{\sqrt2}
  3. The derivative changes from positive to negative there.

    Emax⁡=2kQ33 R2E_{\max}=\frac{2kQ}{3\sqrt3\,R^2}

What this gives usThe maximum on the positive axis occurs at z = R/√2.

Check the result another way

The field is zero at z = 0 and tends to zero at large z; the positive-to-negative derivative change confirms a maximum rather than a minimum.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Locate the strongest axial field by differentiation
Problem: For a positive uniformly charged ring, find where E_z is maximum on the positive axis.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: A uniformly charged ring gives an axial field with a useful maximum
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
E_z=\frac{kQz}{(R^2+z^2)^{3/2}}
Meaning: Uniform ring, axial observation point. The expression is signed through z and Q.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

07 / Electric forces, fields and charge distributions

A finite line approaches both point-charge and infinite-line limits

Consider a uniformly charged straight segment from x = −L to x = +L, and a point a perpendicular distance y > 0 above its midpoint. Symmetric source elements cancel horizontal components. The vertical contribution is kλy dx/(x² + y²)^(3/2).

Integrating from −L to L gives E_y = 2kλL/[y√(L² + y²)]. The parameter L is the half-length, so the total charge is 2λL. Labeling the full length and half-length incorrectly is a common factor-of-two error.

Far from the segment, y ≫ L, the field approaches 2kλL/y² = kQ/y². Very near its midpoint compared with its length, y ≪ L, it approaches 2kλ/y, the infinite-line result. The different distance powers reflect different effective geometries.

The infinite-line approximation is local: the observation distance must be small compared with distances to the ends. It does not imply that a finite real object literally contains infinite charge.

WORKED EXAMPLE

Derive the field instead of selecting a point-charge shortcut

A uniform line charge λ extends from −L to +L. Derive the field magnitude at perpendicular distance y from its midpoint and identify the near-midpoint limit.

Choose an approach

Keep the changing source distance and vertical projection inside the integral.

  1. Use symmetry to integrate only the surviving component.

    Ey=kλy∫−LLdx(x2+y2)3/2E_y=k\lambda y\int_{-L}^{L}\frac{dx}{(x^2+y^2)^{3/2}}
  2. The antiderivative gives the finite-length expression.

    Ey=2kλLyL2+y2E_y=\frac{2k\lambda L}{y\sqrt{L^2+y^2}}
  3. For y much smaller than L, the square root approaches L.

    Ey≈2kλy=λ2πε0yE_y\approx\frac{2k\lambda}{y}=\frac{\lambda}{2\pi\varepsilon_0y}

What this gives usThe near-midpoint field falls as 1/y, unlike the far-away point-charge limit that falls as 1/y².

Check the result another way

The finite expression has units k(C/m)/m = N/C. Its far limit uses the actual total charge 2λL.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Derive the field instead of selecting a point-charge shortcut
Problem: A uniform line charge λ extends from −L to +L. Derive the field magnitude at perpendicular distance y from its midpoint and identify the near-midpoint limit.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: A finite line approaches both point-charge and infinite-line limits
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
Build the physical reasoning before choosing an equation.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

08 / Electric forces, fields and charge distributions

Build a charged disk from concentric rings

A uniformly charged disk can be divided into thin rings of radius s and width ds. Each ring carries dq = σ(2πs ds). At an axial distance z > 0, use the ring’s axial field contribution and integrate s from zero to the disk radius R.

The resulting field is σ/(2ε₀)[1 − z/√(z² + R²)] for positive σ on the positive axis. Near the centre of a very broad disk, z ≪ R, it approaches σ/(2ε₀), independent of distance. This is the ideal infinite-sheet field on one side.

Far away, the bracket is approximately R²/(2z²), so the field becomes σR²/(4ε₀z²) = kQ/z² with Q = σπR². Both limits provide checks on the integration and the prefactor.

The disk’s axial formula is not the field at an arbitrary off-axis point. Symmetry has reduced the calculation only on the axis. Before using a compact formula, confirm that the observation point satisfies its geometry.

Ez=σ2ε0(1−zz2+R2),z>0E_z=\frac{\sigma}{2\varepsilon_0}\left(1-\frac{z}{\sqrt{z^2+R^2}}\right),\qquad z>0

Uniform disk of radius R. The direction reverses on the opposite side for positive surface charge.

WORKED EXAMPLE

Track the area element in a disk calculation

Show how ring elements produce the axial disk field.

Choose an approach

Use dq = 2πσs ds, not a constant charge per radial interval.

  1. Insert each ring’s charge and axial projection.

    Ez=2πkσz∫0Rs ds(z2+s2)3/2E_z=2\pi k\sigma z\int_0^R\frac{s\,ds}{(z^2+s^2)^{3/2}}
  2. Integrate using the derivative of (z² + s²)^(−1/2).

    Ez=2πkσ(1−zz2+R2)E_z=2\pi k\sigma\left(1-\frac{z}{\sqrt{z^2+R^2}}\right)
  3. Replace 2πk by its permittivity form.

    2πk=12ε02\pi k=\frac1{2\varepsilon_0}

What this gives usThe disk result follows from a one-dimensional ring integral because rotational symmetry already cancels transverse components.

Check the result another way

At R = 0 the field vanishes. As R grows without bound at fixed z, the field tends to σ/(2ε₀).

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Track the area element in a disk calculation
Problem: Show how ring elements produce the axial disk field.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Build a charged disk from concentric rings
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
E_z=\frac{\sigma}{2\varepsilon_0}\left(1-\frac{z}{\sqrt{z^2+R^2}}\right),\qquad z>0
Meaning: Uniform disk of radius R. The direction reverses on the opposite side for positive surface charge.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

09 / Electric forces, fields and charge distributions

Electric flux counts a signed normal component through a surface

For a uniform field through a flat area, electric flux is E·A = EA cos θ, where the area vector is perpendicular to the surface. The angle is measured from the normal, not from the plane. A field tangent to the surface gives zero flux through it.

For a curved surface or nonuniform field, sum E·dA over small elements. On a closed surface, the area vector convention points outward. Outgoing field contributes positive flux and incoming field negative flux.

Flux is not the field itself. A closed surface can have zero net flux even with strong fields crossing it, because inward and outward contributions cancel. The quantity has units N·m²/C rather than N/C.

Gauss’s law states that the net electric flux through a closed surface equals enclosed total charge divided by ε₀. Charges outside the surface can change E at its points but contribute zero net enclosed charge and therefore zero net flux contribution through that closed surface.

ΦE=∮E⋅dA=Qencε0\Phi_E=\oint\mathbf E\cdot d\mathbf A=\frac{Q_{\mathrm{enc}}}{\varepsilon_0}

The surface must be closed for this enclosed-charge relation. The general law uses total charge, including any material polarization charge; the examples here use vacuum electrostatics.

WORKED EXAMPLE

Use symmetry only where it exists

A point charge q is at the centre of a cube. Find the total outward flux and the flux through one face. What changes if the charge moves off-centre but remains inside?

Choose an approach

Use Gauss’s law for the total and cubic symmetry only for the centred case.

  1. The closed-surface flux depends on enclosed charge.

    Φtotal=q/ε0\Phi_{\mathrm{total}}=q/\varepsilon_0
  2. At the centre, all six faces are equivalent.

    Φface=q/(6ε0)\Phi_{\mathrm{face}}=q/(6\varepsilon_0)

What this gives usThe centred charge gives q/ε₀ total flux and q/(6ε₀) through each face. Moving it off-centre preserves the total but generally makes the face fluxes unequal.

Check the result another way

No assumption of constant field over a cube face was used. Symmetry equates integrated face fluxes, not local field magnitudes.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Use symmetry only where it exists
Problem: A point charge q is at the centre of a cube. Find the total outward flux and the flux through one face. What changes if the charge moves off-centre but remains inside?

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

STOP & THINK

A closed surface encloses no net charge. Must E be zero everywhere on it?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions / Electric flux counts a signed normal component through a surface
Problem: A closed surface encloses no net charge. Must E be zero everywhere on it?
Choices:
1. Yes, Gauss’s law makes every local field zero
2. No; inward and outward flux can cancel
3. Only if the surface is spherical

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Electric flux counts a signed normal component through a surface
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
\Phi_E=\oint\mathbf E\cdot d\mathbf A=\frac{Q_{\mathrm{enc}}}{\varepsilon_0}
Meaning: The surface must be closed for this enclosed-charge relation. The general law uses total charge, including any material polarization charge; the examples here use vacuum electrostatics.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

10 / Electric forces, fields and charge distributions

Gauss’s law gives a simple field only with sufficient symmetry

To extract E from a flux integral, symmetry must establish its direction and whether its magnitude is constant on the relevant parts of the Gaussian surface. Choosing a convenient surface cannot create symmetry absent from the source distribution.

For an infinite uniform line charge, use a coaxial cylinder. The field is radial and constant on its curved side, while it is tangent to the end caps and gives no flux through them. Gauss’s law gives E(2πrℓ) = λℓ, divided by ε₀, so E = λ/(2πε₀r).

For an infinite uniform charged sheet, use a pillbox crossing the sheet. Equal normal fields leave both caps and no flux leaves the curved side. Thus 2EA = σA/ε₀, giving E = σ/(2ε₀). The factor two counts two equal flux-carrying caps.

For two parallel infinite sheets, superpose their fields region by region. Oppositely charged equal sheets cancel outside and reinforce between them, giving σ/ε₀ between. Equal same-sign sheets cancel between and reinforce outside. A sign diagram is safer than using a memorized capacitor value in every two-sheet situation.

WORKED EXAMPLE

Compare the fields between and outside two sheets

Two ideal infinite sheets carry uniform surface charge densities +σ and −σ. Determine the electric field in the three regions, neglecting any other charges.

Choose an approach

Each sheet has magnitude σ/(2ε₀) on either side, directed away from positive and toward negative charge.

  1. Between the sheets, the two contributions point from positive to negative.

    Ebetween=σ2ε0+σ2ε0=σε0E_{\mathrm{between}}=\frac{\sigma}{2\varepsilon_0}+\frac{\sigma}{2\varepsilon_0}=\frac{\sigma}{\varepsilon_0}
  2. Outside, equal contributions point in opposite directions.

    Eoutside=0E_{\mathrm{outside}}=0

What this gives usThe field is uniform from the positive sheet toward the negative sheet between them and zero outside in the infinite-sheet model.

Check the result another way

The same-sign version reverses which regions cancel. This confirms that sheet signs are part of the reasoning, not just their magnitudes.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Compare the fields between and outside two sheets
Problem: Two ideal infinite sheets carry uniform surface charge densities +σ and −σ. Determine the electric field in the three regions, neglecting any other charges.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Gauss’s law gives a simple field only with sufficient symmetry
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
Build the physical reasoning before choosing an equation.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

11 / Electric forces, fields and charge distributions

Enclosed charge changes with radius inside a charged volume

For a spherically symmetric charge distribution, a concentric Gaussian sphere has radial E with constant magnitude over its surface. The field obeys E(4πr²) = Q_enc(r)/ε₀. Outside the distribution, all charge is enclosed and the field equals that of a point charge at the centre.

Inside a uniformly charged insulating sphere of radius R and total charge Q, the enclosed fraction is the volume fraction r³/R³. Substitution gives E = kQr/R³. The field rises linearly from zero at the centre and matches kQ/R² at the surface.

A thin uniformly charged spherical shell is different: a smaller concentric Gaussian sphere encloses no charge, and spherical symmetry then implies E = 0 inside. Zero enclosed charge alone would not be enough without the symmetry argument.

An insulating sphere with fixed volume charge and a conducting sphere in electrostatic equilibrium have different charge distributions. Do not transfer the linear interior-field formula from the insulating case to a conductor.

E(r)={kQrR3,0≤r≤R,kQr2,r≥R,E(r)=\begin{cases}\dfrac{kQr}{R^3},&0\le r\le R,\\[4pt]\dfrac{kQ}{r^2},&r\ge R,\end{cases}

Uniform positive volume charge in an insulating sphere. The field direction is radially outward; reverse it for negative Q.

WORKED EXAMPLE

Compare interior and exterior points using the correct enclosed charge

A uniformly charged insulating sphere has radius R and surface field magnitude E_s. Find E at r = R/2 and at r = 2R.

Choose an approach

Use the linear interior relation and inverse-square exterior relation separately.

  1. Inside, field magnitude is proportional to radius.

    E(R/2)=12EsE(R/2)=\frac12E_s
  2. Outside, the full charge is enclosed and distance doubles.

    E(2R)=14EsE(2R)=\frac14E_s

What this gives usThe interior point has field E_s/2 and the exterior point E_s/4. Treating the interior as if all charge were at the centre would give the wrong answer.

Check the result another way

At r = R both expressions agree with E_s. At the centre the uniform sphere field vanishes by symmetry.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Worked-example topic: Compare interior and exterior points using the correct enclosed charge
Problem: A uniformly charged insulating sphere has radius R and surface field magnitude E_s. Find E at r = R/2 and at r = 2R.

Guide me through reconstructing the argument myself. Ask why each step is justified before moving to the next.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

STOP & THINK

For the same uniformly charged insulating sphere, what is E(R/2)/E(2R)?

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Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions / Enclosed charge changes with radius inside a charged volume
Problem: For the same uniformly charged insulating sphere, what is E(R/2)/E(2R)?
Requested answer unit: 

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Enclosed charge changes with radius inside a charged volume
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
E(r)=\begin{cases}\dfrac{kQr}{R^3},&0\le r\le R,\\[4pt]\dfrac{kQ}{r^2},&r\ge R,\end{cases}
Meaning: Uniform positive volume charge in an insulating sphere. The field direction is radially outward; reverse it for negative Q.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

12 / Electric forces, fields and charge distributions

Electrostatic equilibrium constrains fields inside conducting material

Mobile charges in a conductor rearrange until the electric field within the conducting material is zero in electrostatic equilibrium. A persistent internal field would keep driving charge motion and contradict that equilibrium condition.

Excess charge on an isolated conductor lies on its surfaces. The external field just outside a smooth conducting surface is normal to it; otherwise a tangential field would move surface charge. A small Gaussian pillbox crossing the surface gives the normal field immediately outside as σ/ε₀ when the inside field is zero.

The value σ/ε₀ refers to the local conductor-surface charge density. The isolated nonconducting infinite-sheet result σ/(2ε₀) describes a different boundary configuration with equal flux on both sides. The factors differ because the boundary conditions differ.

A cavity containing no charge inside a conductor in electrostatic equilibrium is shielded from external electrostatic fields. A cavity containing a charge generally has a nonzero cavity field and induced charge on its inner wall. The conducting material still has zero field. Distinguish the metal from the empty space it surrounds.

STOP & THINK

A charge is placed inside a cavity in a conductor at electrostatic equilibrium. Where must the electric field be zero?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions / Electrostatic equilibrium constrains fields inside conducting material
Problem: A charge is placed inside a cavity in a conductor at electrostatic equilibrium. Where must the electric field be zero?
Choices:
1. Everywhere in the cavity
2. Within the conducting material
3. Everywhere outside the conductor

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Focus: Electrostatic equilibrium constrains fields inside conducting material
Learning goals:
- Use signed Coulomb forces and distinguish a field from the force on a test charge.
- Add source components and identify admissible zero-field regions.
- Set up line, ring and disk integrals with correct charge elements.
- Check field expressions by near and far limits.
- Interpret electric flux as a signed surface integral.
- Use Gauss’s law only with justified symmetry when extracting E.
- Distinguish insulating volume charge, shells and conducting equilibrium.
Equations in this section (LaTeX):
Build the physical reasoning before choosing an equation.

Start by checking the prerequisite idea I need most. Use a simple example, then change one condition to test my understanding.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Back to chapter contents ↑

BRING THE IDEAS TOGETHER

What should stay with you

  • Coulomb forces are vector interactions along the source separation.
  • A negative test charge reverses force relative to a fixed field.
  • Symmetry can cancel components, but cannot replace source-sign reasoning.
  • Continuous charge calculations need both a charge element and a projection.
  • Gauss’s law always constrains total closed-surface flux; a simple local field needs additional symmetry.
  • Zero flux does not imply zero field.
  • The enclosed charge inside a uniform sphere grows as r³.
  • Conducting material has zero electrostatic field at equilibrium, while a charged cavity need not.

RETRIEVE, THEN EXPLAIN

Try it without the examples

Work these out before checking. If an answer surprises you, identify which assumption or step needs another look. A correct choice is most useful when you can explain why the alternatives fail.

SELF CHECK 1

Two point charges remain fixed in magnitude while their separation triples. What is the new-to-old electrostatic force-magnitude ratio? Give at least three significant figures, or an exact fraction.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Problem: Two point charges remain fixed in magnitude while their separation triples. What is the new-to-old electrostatic force-magnitude ratio? Give at least three significant figures, or an exact fraction.
Requested answer unit: 

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

SELF CHECK 2

For a positive ring, the axial maximum occurs at z = R/√2. What is z/R? Give at least three significant figures, or an exact fraction.

Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Problem: For a positive ring, the axial maximum occurs at z = R/√2. What is z/R? Give at least three significant figures, or an exact fraction.
Requested answer unit: 

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

SELF CHECK 3

A large external charge is brought near a closed Gaussian surface without entering it. What happens to its total electric flux?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Problem: A large external charge is brought near a closed Gaussian surface without entering it. What happens to its total electric flux?
Choices:
1. It must increase
2. It is unchanged if enclosed total charge is unchanged
3. It becomes equal to the field at the nearest point

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

SELF CHECK 4

Which element represents charge on a thin uniform ring of radius s and radial width ds cut from a disk?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Problem: Which element represents charge on a thin uniform ring of radius s and radial width ds cut from a disk?
Choices:
1. dq = σ ds
2. dq = 2πσs ds
3. dq = 4πσs² ds

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

SELF CHECK 5

Can choosing a spherical Gaussian surface make the field constant on it for an arbitrary off-centre source distribution?

Choose an answer
Study with a tutor prompt

Copy this into your AI assistant, then describe where you got stuck. It asks the tutor to coach you one step at a time. Check its reasoning against the lesson.

Topic: Electric forces, fields and charge distributions
Problem: Can choosing a spherical Gaussian surface make the field constant on it for an arbitrary off-centre source distribution?
Choices:
1. Yes, the surface determines the field symmetry
2. No, the source distribution determines the relevant symmetry
3. Only if the sphere is very small

Help me choose a model and explain my reasoning before checking my answer.

Tutoring approach:
Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.

APPLY THE CHAPTER

Take the ideas into a problem

Try a complete problem next. Commit to a method before revealing a hint, then compare your reasoning with the worked solution.

Force between two tiny chargesIntermediate · Free sample · Hints and guided reasoningFlux through an enclosing surfaceIntermediate · Free sample · Hints and guided reasoningRead field from labelled voltage contoursIntermediate · Hints and guided reasoningSum a ring without losing directionAdvanced · Hints and guided reasoningDo the electric fields cancel at the midpoint?Beginner · Hints and guided reasoningWhere do the fields cancel?Advanced · Hints and guided reasoningInside a uniformly charged shellIntermediate · Hints and guided reasoningField on both sides of a sheetIntermediate · Hints and guided reasoning

COME BACK TO THE IDEA

What can you explain later?

Try these from memory at your next study session, then again a few days later. Say your reasoning aloud or sketch it before looking. Adjust the gap to what you can explain.

Next study session

At the midpoint between equal positive charges, why can the electric field vanish even though each charge produces a field?

Compare your reasoning

The two fields have equal magnitudes and opposite directions there, so their vector sum is zero. Each contribution remains nonzero; cancellation is a statement about the sum.

Revisit the explanation →

A few days later: change the situation

A closed surface has zero net electric flux. Can you conclude the field is zero everywhere on it?

Compare your reasoning

No. Field can enter in some places and leave in others. Zero flux constrains net enclosed charge, not the field at every point. Symmetry is extra information needed for many field calculations.

Revisit the explanation →

Compare the physical reason, the assumptions and the conclusion. Your wording can differ. If one part is missing, revisit that section and try explaining it again after a break.

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