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PRACTICE / Electrostatic potential energy

Energy gained by a negative probe

An electron starts with kinetic energy 45 eV and reaches a point whose potential is 35 V higher. Only the stationary electrostatic force does work.

What is its final kinetic energy?

Organize the givens & assumptions
  • Initial kinetic energy: 45 eV
  • Final minus initial potential: +35 V

Electron charge −e; use 1 eV = 1.602×10⁻¹⁹ J. The stated trajectory reaches the final point; no other work or radiation loss.

  1. A45 eV45\ \mathrm{eV}
  2. B80 eV80\ \mathrm{eV}
  3. C10 eV10\ \mathrm{eV}
  4. D35 eV35\ \mathrm{eV}

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