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PRACTICE / Diode rectification

Average the rectified waveform

An ideal full-wave bridge rectifier applies the absolute value of a 10 V peak sinusoidal voltage to a 100 Ω resistor. No smoothing capacitor is fitted.

Find the time-averaged load current.

Organize the givens & assumptions
  • Input peak Vp = 10 V
  • Load R = 100 Ω
  • Full-wave unsmoothed output

Ideal zero-drop diodes, resistive load, steady sinusoidal input and no energy-storage filter.

  1. A0.10π A\frac{0.10}{\pi}\ \mathrm A
  2. B0.20π A\frac{0.20}{\pi}\ \mathrm A
  3. C0.102 A\frac{0.10}{\sqrt2}\ \mathrm A
  4. D0.10 A0.10\ \mathrm A

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