THE PRACTICE STUDIO
Go slowly. Ask why. Make it yours.
PRACTICE / Calorimetry
Two portions of water reach equilibrium
Mix 0.20 kg of water at 80°C with 0.30 kg at 20°C in an insulated negligible-capacity container.
Find the final temperature in °C.
Organize the givens & assumptions
- mhot = 0.20 kg
- Thot = 80°C
- mcold = 0.30 kg
- Tcold = 20°C
Insulated negligible-capacity container; constant common water specific heat; no evaporation or phase change.
Study with a tutor prompt
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Problem: Two portions of water reach equilibrium Mix 0.20 kg of water at 80°C with 0.30 kg at 20°C in an insulated negligible-capacity container. Question: Find the final temperature in °C. Givens: - mhot = 0.20 kg - Thot = 80°C - mcold = 0.30 kg - Tcold = 20°C Assumptions: Insulated negligible-capacity container; constant common water specific heat; no evaporation or phase change. Choices (LaTeX): A. 50^\circ\mathrm C B. 56^\circ\mathrm C C. 100^\circ\mathrm C D. 44^\circ\mathrm C Ask for my approach first. Help me distinguish a physical misconception from an algebra error without revealing which choice is correct. Tutoring approach: Act as a patient physics tutor. Ask what I understand and what I have tried, then wait for my reply. Teach one step at a time; do not give the final answer or a complete solution immediately. Start with a physical picture. Define unfamiliar symbols and operators, explain signs and units, and state the model's assumptions. Give progressively stronger hints only when I need them. Ask me to predict a change before calculating it. When I finish, help me check dimensions and a limiting case, then ask one related transfer question. If information is missing or ambiguous, ask rather than inventing it. Distinguish exact results from approximations and acknowledge uncertainty.
Start with the smallest hint.
Work through it with me.
One decision at a time. Pause, predict, then unpack the algebra.
The same specific heat cancels, leaving a mass-weighted temperature average.
Choose a physical relation
Energy lost by hot water equals energy gained by cold water because no energy escapes the mixture.
Isolate what is asked
The same specific heat cancels, leaving a mass-weighted temperature average.
Why is this step valid?
The common specific heat cancels, leaving a mass-weighted average of starting temperatures.
Substitute and interpret
Final temperature is 44°C, closer to the colder sample's temperature because it has more mass.
Heat lost by the warm water equals heat gained by the cool water.
TRY THE IDEA AGAIN
If the two starting masses were equal, what final temperature would follow?
YOUR LEARNING NOTE
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